What is the critical (x^2)/(4-x^2) ?

The critical (x^2)/(4-x^2) is x=0

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critical (x^2)/(4-x^2)

critical points

\frac{x ^{2}}{4 - x ^{2}}

x = 0

Solution steps

\frac{x ^{2}}{4 - x ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = - 2, x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2}}{4 - x ^{2}} : x < - 2 or - 2 < x < 2 or x > 2

\frac{x ^{2}}{4 - x ^{2}}

is not defined at

x = - 2, x = 2

, therefore:

x = 0

\frac{x ^{2} + 1}{x ^{2} - 4}

sin (x) - x

f (x) = x^{3} y + 12 x^{2} - 8 y

f (x, y) = 2 x^{2} + x y^{2} - 6 x y + 5 x + 2

f (x) = x 8 - x^{2}