What is the critical f(x)=4+x^3+y^3-3xy ?

The critical f(x)=4+x^3+y^3-3xy is (0,0),(1,1)

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critical f(x)=4+x^3+y^3-3xy

critical points

f (x) = 4 + x^{3} + y^{3} - 3 x y

(0, 0), (1, 1)

Solution steps

4 + x^{3} + y^{3} - 3 x y

Find where

\nabla f (x, y)

is equal to zero or undefined

(0, 0), (1, 1)

f (x) = x y^{2} + 2 x y + 3 x^{3} - 3 x

6 x^{2} - x^{3}

\frac{x}{x ^{2} + 9}

x (1 - x^{2})^{2}

f (x, y) = x y + \frac{8}{x} + \frac{8}{y}

What is the critical f(x)=4+x^3+y^3-3xy ?
The critical f(x)=4+x^3+y^3-3xy is (0,0),(1,1)