What is the critical f(x)=(x^2+1)/(x^2-4) ?

The critical f(x)=(x^2+1)/(x^2-4) is x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical f(x)=(x^2+1)/(x^2-4)

critical points

f (x) = \frac{x ^{2} + 1}{x ^{2} - 4}

x = 0

Solution steps

\frac{x ^{2} + 1}{x ^{2} - 4}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = - 2, x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} + 1}{x ^{2} - 4} : x < - 2 or - 2 < x < 2 or x > 2

\frac{x ^{2} + 1}{x ^{2} - 4}

is not defined at

x = - 2, x = 2

, therefore:

x = 0

f (x) = x - \frac{1}{2} y^{2} - \frac{1}{3} x^{3} + y + 6

f (x, y) = x^{3} + y^{3} - 3 x - 3 y + 4

f (x) = x^{3} + 2 x^{2} + 1

\frac{x}{x - 1}

What is the critical f(x)=(x^2+1)/(x^2-4) ?
The critical f(x)=(x^2+1)/(x^2-4) is x=0