What is the critical f(x)=(e^{4x})/(x+1) ?

The critical f(x)=(e^{4x})/(x+1) is x=-3/4

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critical f(x)=(e^{4x})/(x+1)

critical points

f (x) = \frac{e ^{4 x}}{x + 1}

x = - \frac{3}{4}

Solution steps

\frac{e ^{4 x}}{x + 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{3}{4}, x = - 1

Identify critical points not in

f (x)

domain

Domain of

\frac{e ^{4 x}}{x + 1} : x < - 1 or x > - 1

\frac{e ^{4 x}}{x + 1}

is not defined at

x = - 1

, therefore:

x = - \frac{3}{4}

x - 3 x^{\frac{1}{3}}

f (x) = (x - 4)^{2} + 10

f (x, y) = (x^{2} + y^{2}) e^{y^{2} - x^{2}}

f (x, y) = 100 + 4 x - 9 y + 2 x y - x^{2} + y^{3}

f (x) = x^{2} - x

What is the critical f(x)=(e^{4x})/(x+1) ?
The critical f(x)=(e^{4x})/(x+1) is x=-3/4