What is the inverse of f(x)=(sqrt(7y+637))/7-3 ?

The inverse of f(x)=(sqrt(7y+637))/7-3 is 7(y^2+6y-4)

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inverse of f(x)=(sqrt(7y+637))/7-3

inverse

f (x) = \frac{7 y + 637}{7} - 3

7 (y^{2} + 6 y - 4)

Solution steps

x = \frac{7 y + 637}{7} - 3

Replace

y

with

x

y = \frac{7 x + 637}{7} - 3

Solve for

x, y = \frac{7 x + 637}{7} - 3

7 (y^{2} + 6 y - 4)

f (x) = (0.33)^{x}

f (x) = e^{2 x} + 1

f (x) = \frac{3 x + 7}{6 x}

f (x) = \frac{x - 2}{2}

f (x) = 4 sin (\frac{1}{π} x - 2) + 8

What is the inverse of f(x)=(sqrt(7y+637))/7-3 ?
The inverse of f(x)=(sqrt(7y+637))/7-3 is 7(y^2+6y-4)