What is the critical f(x,y)=4+x^3+y^3-3xy ?

The critical f(x,y)=4+x^3+y^3-3xy is (0,0),(1,1)

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critical f(x,y)=4+x^3+y^3-3xy

critical points

f (x, y) = 4 + x^{3} + y^{3} - 3 x y

(0, 0), (1, 1)

Solution steps

4 + x^{3} + y^{3} - 3 x y

Find where

\nabla f (x, y)

is equal to zero or undefined

(0, 0), (1, 1)

4 x^{3} - 4 x

f (x, y) = x^{3} y + 12 x^{2} - 8 y

f (x) = x^{2} - 6 x + 10

2 x

f (x, y) = x^{2} + x y + y^{2} + y

What is the critical f(x,y)=4+x^3+y^3-3xy ?
The critical f(x,y)=4+x^3+y^3-3xy is (0,0),(1,1)