What is the critical f(x)=x^2-8x+6ln(x) ?

The critical f(x)=x^2-8x+6ln(x) is x=1,x=3

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critical f(x)=x^2-8x+6ln(x)

critical points

f (x) = x^{2} - 8 x + 6 ln (x)

x = 1, x = 3

Solution steps

x^{2} - 8 x + 6 ln (x)

Find where

f^{'} (x)

is equal to zero or undefined

x = 1, x = 3, x = 0

Identify critical points not in

f (x)

domain

Domain of

x^{2} - 8 x + 6 ln (x) : x > 0

x^{2} - 8 x + 6 ln (x)

is not defined at

x = 0

, therefore:

x = 1, x = 3

f (x) = \frac{x}{1 + x}

- 0.1 x^{3} + 6 x^{2} + 400

f (x) = 2 x^{2} - 6 x + 8

x^{3} - 3 x^{2} + 3

x^{4} ln (x)

What is the critical f(x)=x^2-8x+6ln(x) ?
The critical f(x)=x^2-8x+6ln(x) is x=1,x=3