What is the critical f(x)=(x^2-3)/(x-2) ?

The critical f(x)=(x^2-3)/(x-2) is x=1,x=3

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critical f(x)=(x^2-3)/(x-2)

critical points

f (x) = \frac{x ^{2} - 3}{x - 2}

x = 1, x = 3

Solution steps

\frac{x ^{2} - 3}{x - 2}

Find where

f^{'} (x)

is equal to zero or undefined

x = 1, x = 3, x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 3}{x - 2} : x < 2 or x > 2

\frac{x ^{2} - 3}{x - 2}

is not defined at

x = 2

, therefore:

x = 1, x = 3

f (x) = x^{\frac{4}{5}} (x - 1)^{2}

f (x) = 80 x^{3} - 3 x^{5}

y = x (1 - x^{2})^{2}

f (x) = ln (1 + x^{2})

f (x) = - 2 x^{2} - 12 x - 13

What is the critical f(x)=(x^2-3)/(x-2) ?
The critical f(x)=(x^2-3)/(x-2) is x=1,x=3