What is the critical f(x)=(x^2-3x-4)/(x-2) ?

The critical f(x)=(x^2-3x-4)/(x-2) is None

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critical f(x)=(x^2-3x-4)/(x-2)

critical points

f (x) = \frac{x ^{2} - 3 x - 4}{x - 2}

None

Solution steps

\frac{x ^{2} - 3 x - 4}{x - 2}

Find where

f^{'} (x)

is equal to zero or undefined

x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 3 x - 4}{x - 2} : x < 2 or x > 2

\frac{x ^{2} - 3 x - 4}{x - 2}

is not defined at

x = 2

, therefore:

None

\frac{d}{d x} (\frac{x y}{x ^{2} - y ^{2}})

f (x, y) = x^{3} - 2 x y + y^{2} + 4

f (x) = x^{3} - 3 x (y - 2) + (y - 2)^{3}

f (x) = x^{3} - 9 x^{2} + 24 x - 10

What is the critical f(x)=(x^2-3x-4)/(x-2) ?
The critical f(x)=(x^2-3x-4)/(x-2) is None