What is the critical f(x)=|x^2+6x| ?

The critical f(x)=|x^2+6x| is x=-6,x=-3,x=0

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critical f(x)=|x^2+6x|

critical points

f (x) = x^{2} + 6 x

x = - 6, x = - 3, x = 0

Solution steps

x^{2} + 6 x

Absolute value functions are piecewise functions

Find the function intervals:

x < - 6, x = - 6, - 6 < x < 0, x = 0, x > 0

Evaluate the function behavior for each interval

Find where

f^{'} (x)

is equal to zero or undefined

x = - 6, x = - 3, x = 0

f (x) = x^{4} - 5 x^{3}

x^{3} - 6 x^{2} + 9 x

f (x) = x^{4} - 3 x^{2} - 2 x

f (x) = x^{4} (x - 1)^{3}

f (x) = 3 x^{2} - 12 x + 9

What is the critical f(x)=|x^2+6x| ?
The critical f(x)=|x^2+6x| is x=-6,x=-3,x=0