What is the critical f(x)=sec^2(x) ?

The critical f(x)=sec^2(x) is x=pin

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critical f(x)=sec^2(x)

critical points

f (x) = sec^{2} (x)

x = πn

Solution steps

sec^{2} (x)

Find where

f^{'} (x)

is equal to zero or undefined

x = πn, x = \frac{π}{2} + πn

Identify critical points not in

f (x)

domain

Domain of

sec^{2} (x) : πn \leq x < \frac{π}{2} + πn or \frac{π}{2} + πn < x < π + πn

sec^{2} (x)

is not defined at

x = \frac{π}{2} + πn

, therefore:

x = πn

4 x^{3} + 3 x^{2} - 6 x + 1

f (x, y) = 2 x^{2} + 3 x y + y^{2} + a x + 5

f (x) = x^{3} - 4 x

x^{3} - 12 x + 1

sin (2 x), 0 \leq x \leq 2 π