What is the critical f(x)=(x^2+9)/x ?

The critical f(x)=(x^2+9)/x is x=-3,x=3

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critical f(x)=(x^2+9)/x

critical points

f (x) = \frac{x ^{2} + 9}{x}

x = - 3, x = 3

Solution steps

\frac{x ^{2} + 9}{x}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 3, x = 3, x = 0

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} + 9}{x} : x < 0 or x > 0

\frac{x ^{2} + 9}{x}

is not defined at

x = 0

, therefore:

x = - 3, x = 3

f (x, y) = 4 x^{3} - 12 x + 3 x y^{2}

f (x, y) = 3 x e^{y} - x^{3} - e^{3 y}

f (x) = x^{5} - 5 x^{3} - 20 x - 2

x^{\frac{1}{3}} (x - 4)

f (x) = 3 x^{2} + 6 x