What is the critical f(x)=(x^4+1)/(x^2) ?

The critical f(x)=(x^4+1)/(x^2) is x=-1,x=1

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critical f(x)=(x^4+1)/(x^2)

critical points

f (x) = \frac{x ^{4} + 1}{x ^{2}}

x = - 1, x = 1

Solution steps

\frac{x ^{4} + 1}{x ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 1, x = 0

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{4} + 1}{x ^{2}} : x < 0 or x > 0

\frac{x ^{4} + 1}{x ^{2}}

is not defined at

x = 0

, therefore:

x = - 1, x = 1

f (x) = cos^{2} (x) + sin (x)

y = \frac{1}{3} x^{3} + \frac{1}{2} x^{2} - 6 x + 8

f (x) = 20 x^{3} - 3 x^{5}

f (x) = \frac{x}{( x + 1 ) ^{2}}

f (x) = x^{2} + 8 x + 16

What is the critical f(x)=(x^4+1)/(x^2) ?
The critical f(x)=(x^4+1)/(x^2) is x=-1,x=1