What is the domain of (x+3)/(x^2+4x-5) ?

The domain of (x+3)/(x^2+4x-5) is x 1

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domain of (x+3)/(x^2+4x-5)

domain

\frac{x + 3}{x ^{2} + 4 x - 5}

x < - 5 or - 5 < x < 1 or x > 1

Solution steps

Find undefined (singularity) points:

x = 1, x = - 5

The function domain

x < - 5 or - 5 < x < 1 or x > 1

\frac{9 - 3 x}{x - 5}

\frac{x ^{2} + 4 x + 3}{x ^{2} - 1}

f (x) = \frac{x ^{2} - 9}{3 x + 6}

f (x) = (x + 3)^{2} - 2

y = ln (x - 1) - ln (2) - 1

What is the domain of (x+3)/(x^2+4x-5) ?
The domain of (x+3)/(x^2+4x-5) is x<-5\lor-5<x<1\lor x>1