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Popular >

range of 2x^2-8

Solution

range

2 x^{2} - 8

Solution

f (x) \geq - 8

+1

Interval Notation

[- 8, \infty)

Solution steps

Vertex of

2 x^{2} - 8 :

Minimum

(0, - 8)

For a parabola

a x^{2} + b x + c

with Vertex

(x_{v}, y_{v})

If

a < 0

the range is

f (x) \leq y_{v}

If

a > 0

the range is

f (x) \geq y_{v}

a = 2,

Vertex

(x_{v}, y_{v}) = (0, - 8)

f (x) \geq - 8

Popular Examples

simplify (-6.4)(-9.12)simplify

(- 6.4) (- 9.12)

y = x^{2} + 4

shift cot(x)shift

cot (x)

monotone f(x)=x^{4/5}monotone intervals

f (x) = x^{\frac{4}{5}}

extreme f(x)=-x^3+3x^2-3x+1 extreme points

f (x) = - x^{3} + 3 x^{2} - 3 x + 1

Frequently Asked Questions (FAQ)

What is the range of 2x^2-8 ?
The range of 2x^2-8 is f(x)>=-8