What is the critical f(x)=(x^2)/((x-1)) ?

The critical f(x)=(x^2)/((x-1)) is x=0,x=2

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critical f(x)=(x^2)/((x-1))

critical points

f (x) = \frac{x ^{2}}{( x - 1 )}

x = 0, x = 2

Solution steps

\frac{x ^{2}}{x - 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = 2, x = 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2}}{x - 1} : x < 1 or x > 1

\frac{x ^{2}}{x - 1}

is not defined at

x = 1

, therefore:

x = 0, x = 2

f (x, y) = x^{3} - y^{3} - 2 x y + 6

\frac{d}{d x} (\frac{2 x y}{x ^{2} + 2 y ^{2}})

x^{3} - 3 x^{2} - 9 x + 4

f (x) = \frac{1}{4} x^{4} - x^{3} - 5 x^{2}

y = \frac{x ^{2} - 4}{x ^{2} + 4}

What is the critical f(x)=(x^2)/((x-1)) ?
The critical f(x)=(x^2)/((x-1)) is x=0,x=2