What is the critical f(x)=x^3-3x^2-9x ?

The critical f(x)=x^3-3x^2-9x is x=-1,x=3

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critical f(x)=x^3-3x^2-9x

critical points

f (x) = x^{3} - 3 x^{2} - 9 x

x = - 1, x = 3

Solution steps

x^{3} - 3 x^{2} - 9 x

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 3

Identify critical points not in

f (x)

domain

Domain of

x^{3} - 3 x^{2} - 9 x : - \infty < x < \infty

All critical points are in domain

x = - 1, x = 3

f (x) = 2 x + 3

x^{4}

f (x) = 2 x^{2} + 2 x y + a y^{2} + 2 x - 3

f (x) = x^{\frac{4}{5}} (x - 2)^{2}

x^{3} + 3 x^{2} - 24 x

What is the critical f(x)=x^3-3x^2-9x ?
The critical f(x)=x^3-3x^2-9x is x=-1,x=3