What is the critical f(x)= x/((1-x)^2) ?

The critical f(x)= x/((1-x)^2) is x=-1

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critical f(x)= x/((1-x)^2)

critical points

f (x) = \frac{x}{( 1 - x ) ^{2}}

x = - 1

Solution steps

\frac{x}{( 1 - x ) ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x}{( 1 - x ) ^{2}} : x < 1 or x > 1

\frac{x}{( 1 - x ) ^{2}}

is not defined at

x = 1

, therefore:

x = - 1

f (x, y) = 2 x^{3} + y^{4}

f (x, y) = x^{2} + 4 y^{2} - 6 x + 16 y

f (x) = x^{2} + 4 x y + y^{2} + y^{3}

f (x) = 3 x^{4} + 8 x^{3} - 18 x^{2}

f (x) = (5 - x) (x + 1)^{2}