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Popular >

critical 1/(x^2-9)

Solution

critical points

\frac{1}{x ^{2} - 9}

Solution

x = 0

Solution steps

\frac{1}{x ^{2} - 9}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = - 3, x = 3

Identify critical points not in

f (x)

domain

Domain of

\frac{1}{x ^{2} - 9} : x < - 3 or - 3 < x < 3 or x > 3

\frac{1}{x ^{2} - 9}

is not defined at

x = - 3, x = 3

, therefore:

x = 0

Popular Examples

critical f(x)= 1/(x^2-9)critical points

f (x) = \frac{1}{x ^{2} - 9}

critical f(x)=e^x(8-x^2)critical points

f (x) = e^{x} (8 - x^{2})

critical 1/(x^3-x)critical points

\frac{1}{x ^{3} - x}

critical x^3+x^2-8x+5 critical points

x^{3} + x^{2} - 8 x + 5

critical f(x,y)=xy+ln(x)+32y^2 critical points

f (x, y) = x y + ln (x) + 32 y^{2}

Frequently Asked Questions (FAQ)

What is the critical 1/(x^2-9) ?
The critical 1/(x^2-9) is x=0