What is the critical f(x)=sqrt(x)ln(x) ?

The critical f(x)=sqrt(x)ln(x) is x= 1/(e^2)

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critical f(x)=sqrt(x)ln(x)

critical points

f (x) = x ln (x)

x = \frac{1}{e ^{2}}

Solution steps

x ln (x)

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{1}{e ^{2}}, x = 0

Identify critical points not in

f (x)

domain

Domain of

x ln (x) : x > 0

x ln (x)

is not defined at

x = 0

, therefore:

x = \frac{1}{e ^{2}}

f (x) = 6 x^{3} - 9 x^{2} - 108 x

f (x) = x^{2} x + 5

f (x, y) = e^{y} (y^{2} - x^{2})

f (x) = e^{3 x} (36 x^{2} + 4)

f (x) = x^{3} - 12 x - 4

What is the critical f(x)=sqrt(x)ln(x) ?
The critical f(x)=sqrt(x)ln(x) is x= 1/(e^2)