What is the critical (x-x^2)/(x-8) ?

The critical (x-x^2)/(x-8) is x=2(4-sqrt(14)),x=2(4+sqrt(14))

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critical (x-x^2)/(x-8)

critical points

\frac{x - x ^{2}}{x - 8}

x = 2 (4 - 14), x = 2 (4 + 14)

Solution steps

\frac{x - x ^{2}}{x - 8}

Find where

f^{'} (x)

is equal to zero or undefined

x = 2 (4 - 14), x = 2 (4 + 14), x = 8

Identify critical points not in

f (x)

domain

Domain of

\frac{x - x ^{2}}{x - 8} : x < 8 or x > 8

\frac{x - x ^{2}}{x - 8}

is not defined at

x = 8

, therefore:

x = 2 (4 - 14), x = 2 (4 + 14)

x^{3} - 6 x^{2} + 9 x + 2

x^{2} + 2 x + 2

f (x) = 4 x^{3} - 48 x^{2} + 6

f (x) = - 4 x^{3} - 2 x^{2} + 16 x + 5

What is the critical (x-x^2)/(x-8) ?
The critical (x-x^2)/(x-8) is x=2(4-sqrt(14)),x=2(4+sqrt(14))