What is the monotone sqrt(2x^2-17) ?

The monotone sqrt(2x^2-17) is Decreasing:-infinity <x<-sqrt(17/2),Increasing:sqrt(17/2)<x<infinity

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monotone sqrt(2x^2-17)

monotone intervals

2 x^{2} - 17

Decreasing : - \infty < x < - \frac{17}{2}, Increasing : \frac{17}{2} < x < \infty

Solution steps

f^{'} (x) = \frac{2 x}{2 x ^{2} - 17}

Find intervals:

Decreasing

: - \infty < x < - \frac{17}{2},

Increasing

: \frac{17}{2} < x < \infty

Decreasing : - \infty < x < - \frac{17}{2}, Increasing : \frac{17}{2} < x < \infty

y = 15

y = 4 x + 2, at 2, 2

f (x) = 5 x^{2} - 2

f (x) = - 30 x^{2} + 28 x - 6

f (x) = \frac{x - 3}{x ^{2} - 4}

What is the monotone sqrt(2x^2-17) ?
The monotone sqrt(2x^2-17) is Decreasing:-infinity <x<-sqrt(17/2),Increasing:sqrt(17/2)<x<infinity