What is the critical f(x)=(x-4)/(-4x^2+4) ?

The critical f(x)=(x-4)/(-4x^2+4) is x=4-sqrt(15),x=4+sqrt(15)

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critical f(x)=(x-4)/(-4x^2+4)

critical points

f (x) = \frac{x - 4}{- 4 x ^{2} + 4}

x = 4 - 15, x = 4 + 15

Solution steps

\frac{x - 4}{- 4 x ^{2} + 4}

Find where

f^{'} (x)

is equal to zero or undefined

x = 4 - 15, x = 4 + 15, x = - 1, x = 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x - 4}{- 4 x ^{2} + 4} : x < - 1 or - 1 < x < 1 or x > 1

\frac{x - 4}{- 4 x ^{2} + 4}

is not defined at

x = - 1, x = 1

, therefore:

x = 4 - 15, x = 4 + 15

f (x, y) = x^{3} y + 6 x^{2} - y

\frac{3 x}{x ^{2} - 16}

4 x^{3} - 16 x

f (x, y) = x^{2} - 3 x y - 1

2 cos (x)

What is the critical f(x)=(x-4)/(-4x^2+4) ?
The critical f(x)=(x-4)/(-4x^2+4) is x=4-sqrt(15),x=4+sqrt(15)