What is the critical (x^2-3)/(x+2) ?

The critical (x^2-3)/(x+2) is x=-3,x=-1

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critical (x^2-3)/(x+2)

critical points

\frac{x ^{2} - 3}{x + 2}

x = - 3, x = - 1

Solution steps

\frac{x ^{2} - 3}{x + 2}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 3, x = - 1, x = - 2

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 3}{x + 2} : x < - 2 or x > - 2

\frac{x ^{2} - 3}{x + 2}

is not defined at

x = - 2

, therefore:

x = - 3, x = - 1

f (x) = (x - 8) e^{x}

f (x) = (x^{2} + y^{2}) e^{x^{2} - y^{2}}

f (x, y) = x y^{3} + x^{2}

f (x, y) = 3 x - x^{2} y^{2} + 2 x^{3}

f (x) = \frac{( x - 1 )}{x + 3}