What is the critical f(x)=(3x^2-3x)/(2x-x^2) ?

The critical f(x)=(3x^2-3x)/(2x-x^2) is None

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critical f(x)=(3x^2-3x)/(2x-x^2)

critical points

f (x) = \frac{3 x ^{2} - 3 x}{2 x - x ^{2}}

None

Solution steps

\frac{3 x ^{2} - 3 x}{2 x - x ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{3 x ^{2} - 3 x}{2 x - x ^{2}} : x < 0 or 0 < x < 2 or x > 2

\frac{3 x ^{2} - 3 x}{2 x - x ^{2}}

is not defined at

x = 2

, therefore:

None

f (x) = \frac{x ^{2} - 4}{1 - x ^{2}}

f (x) = \frac{( 2 x - 1 )}{x - 1}

f (x, y) = - \frac{1}{2 x ^{2} + 11 x y + 5 y ^{2} + 18}

\frac{1 + x}{x}

x^{4} + 2 x^{3} + 2 x^{2} + 4 x

What is the critical f(x)=(3x^2-3x)/(2x-x^2) ?
The critical f(x)=(3x^2-3x)/(2x-x^2) is None