What is the critical f(x)=(x^3)/(x^2-3) ?

The critical f(x)=(x^3)/(x^2-3) is x=-3,x=0,x=3

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critical f(x)=(x^3)/(x^2-3)

critical points

f (x) = \frac{x ^{3}}{x ^{2} - 3}

x = - 3, x = 0, x = 3

Solution steps

\frac{x ^{3}}{x ^{2} - 3}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 3, x = 0, x = 3, x = - 3, x = 3

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{3}}{x ^{2} - 3} : x < - 3 or - 3 < x < 3 or x > 3

\frac{x ^{3}}{x ^{2} - 3}

is not defined at

x = - 3, x = 3

, therefore:

x = - 3, x = 0, x = 3

x^{4} - 8 x^{2} + 16

y = 3 x^{3} - 2 x^{2} - 5 x

f (x) = 1 + 80 x^{3} + 5 x^{4} - 2 x^{5}

f (x, y) = e^{x y}

f (x) = x^{3} - 6 x^{2} + 4

What is the critical f(x)=(x^3)/(x^2-3) ?
The critical f(x)=(x^3)/(x^2-3) is x=-3,x=0,x=3