What is the critical f(x)=-(8x)/(x^2-4) ?

The critical f(x)=-(8x)/(x^2-4) is None

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critical f(x)=-(8x)/(x^2-4)

critical points

f (x) = - \frac{8 x}{x ^{2} - 4}

None

Solution steps

- \frac{8 x}{x ^{2} - 4}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 2

Identify critical points not in

f (x)

domain

Domain of

- \frac{8 x}{x ^{2} - 4} : x < - 2 or - 2 < x < 2 or x > 2

- \frac{8 x}{x ^{2} - 4}

is not defined at

x = - 2, x = 2

, therefore:

None

f (x) = x x + 2

f (x) = 3 x^{2} - 3 x + 4

f (x) = 4 x^{4} + 4 x^{3} - 4 x^{2} + 8

f (x, y) = x^{3} + y^{2} - y - x y + 5

g (y) = \frac{y - 1}{y ^{2} - 3 y + 3}

What is the critical f(x)=-(8x)/(x^2-4) ?
The critical f(x)=-(8x)/(x^2-4) is None