What is the critical f(x)=((x^2-4))/(x-1) ?

The critical f(x)=((x^2-4))/(x-1) is None

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critical f(x)=((x^2-4))/(x-1)

critical points

f (x) = \frac{( x ^{2} - 4 )}{x - 1}

None

Solution steps

\frac{x ^{2} - 4}{x - 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = 1

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 4}{x - 1} : x < 1 or x > 1

\frac{x ^{2} - 4}{x - 1}

is not defined at

x = 1

, therefore:

None

f (x) = - x^{2} + 2 x + 2

2 x^{3} + 3 x^{2} - 12 x + 5

x^{3} y + 12 x^{2} - 8 y

f (x) = \frac{1}{1 - x ^{2}}

f (x) = x^{3} - 3 x + 3

What is the critical f(x)=((x^2-4))/(x-1) ?
The critical f(x)=((x^2-4))/(x-1) is None