What is the extreme f(x)=2xe^{-5x} ?

The extreme f(x)=2xe^{-5x} is Maximum(1/5 , 2/(5e))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=2xe^{-5x}

extreme points

f (x) = 2 x e^{- 5 x}

Maximum (\frac{1}{5}, \frac{2}{5 e})

Solution steps

Find the critical points:

x = \frac{1}{5}

Domain of

2 x e^{- 5 x} : - \infty < x < \infty

Find intervals:

Increasing

: - \infty < x < \frac{1}{5},

Decreasing

: \frac{1}{5} < x < \infty

Plug the extreme point

x = \frac{1}{5}

into

2 x e^{- 5 x} \Rightarrow y = \frac{2}{5 e}

Maximum (\frac{1}{5}, \frac{2}{5 e})

f (x) = \frac{- 2}{x + 3}

\frac{1}{x}

f (x) = (\frac{1}{2})^{x}

f (x) = \frac{5}{5 + 3 x}

4 y - 7 = - 2 (4 - 2 x)

What is the extreme f(x)=2xe^{-5x} ?
The extreme f(x)=2xe^{-5x} is Maximum(1/5 , 2/(5e))