What is the critical f(x)=(16x)/((x^2+4)^2) ?

The critical f(x)=(16x)/((x^2+4)^2) is x=-2/(sqrt(3)),x= 2/(sqrt(3))

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critical f(x)=(16x)/((x^2+4)^2)

critical points

f (x) = \frac{16 x}{( x ^{2} + 4 ) ^{2}}

x = - \frac{2}{3}, x = \frac{2}{3}

Solution steps

\frac{16 x}{( x ^{2} + 4 ) ^{2}}

Find where

f^{'} (x)

is equal to zero or undefined

x = - \frac{2}{3}, x = \frac{2}{3}

Identify critical points not in

f (x)

domain

Domain of

\frac{16 x}{( x ^{2} + 4 ) ^{2}} : - \infty < x < \infty

All critical points are in domain

x = - \frac{2}{3}, x = \frac{2}{3}

f (x, y) = x y - x^{4} - y^{4}

80 x^{3} - 3 x^{5}

2 x - x^{2} - x y

2 x^{3} + x^{2} + 2 x

f (x) = \frac{x ^{3}}{4} - 3 x

What is the critical f(x)=(16x)/((x^2+4)^2) ?
The critical f(x)=(16x)/((x^2+4)^2) is x=-2/(sqrt(3)),x= 2/(sqrt(3))