What is the critical f(x)=4x^2ln(x) ?

The critical f(x)=4x^2ln(x) is x= 1/(sqrt(e))

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critical f(x)=4x^2ln(x)

critical points

f (x) = 4 x^{2} ln (x)

x = \frac{1}{e}

Solution steps

4 x^{2} ln (x)

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{1}{e}, x = 0

Identify critical points not in

f (x)

domain

Domain of

4 x^{2} ln (x) : x > 0

4 x^{2} ln (x)

is not defined at

x = 0

, therefore:

x = \frac{1}{e}

f (x, y) = x^{3} y + 3 x^{2} - y

f (x) = 3 x^{4} - 4 x^{3} - 12 x^{2} + 5

x^{4} - 2 x^{2} - 3

x^{2} - 4 x + 5

f (x) = 16 - x^{2}

What is the critical f(x)=4x^2ln(x) ?
The critical f(x)=4x^2ln(x) is x= 1/(sqrt(e))