What is the critical f(x)=((e^{2x}))/(x-3) ?

The critical f(x)=((e^{2x}))/(x-3) is x= 7/2

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critical f(x)=((e^{2x}))/(x-3)

critical points

f (x) = \frac{( e ^{2 x} )}{x - 3}

x = \frac{7}{2}

Solution steps

\frac{e ^{2 x}}{x - 3}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{7}{2}, x = 3

Identify critical points not in

f (x)

domain

Domain of

\frac{e ^{2 x}}{x - 3} : x < 3 or x > 3

\frac{e ^{2 x}}{x - 3}

is not defined at

x = 3

, therefore:

x = \frac{7}{2}

(x^{2} + 11) (4 - x^{2})

f (x) = \frac{x ^{3}}{3} + \frac{9 x ^{2}}{2} + 20 x - 2

f (x) = x e^{3 - \frac{x}{4}}

y = x^{3} - 3 x + 2

f (x, y) = 2 x^{3} + 2 y^{3} - 9 x^{2} + 3 y^{2} - 12 y

What is the critical f(x)=((e^{2x}))/(x-3) ?
The critical f(x)=((e^{2x}))/(x-3) is x= 7/2