What is the critical f(x)=\sqrt[3]{x^2(x-2)^2} ?

The critical f(x)=\sqrt[3]{x^2(x-2)^2} is x=0,x=1,x=2

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critical f(x)=\sqrt[3]{x^2(x-2)^2}

critical points

x = 0, x = 1, x = 2

Solution steps

Find where

f^{'} (x)

is equal to zero or undefined

x = 1, x = 0, x = 2

Identify critical points not in

f (x)

domain

Domain of

All critical points are in domain

x = 0, x = 1, x = 2

f (x) = - 3 x^{2} + 6 x

f (x) = 9 - 2 x + 4 y - x^{2} - 4 y^{2}

f (x) = x^{2} - x + 1

x^{\frac{1}{3}} (x + 3)^{\frac{2}{3}}

f (x) = 4 x^{3} - x^{4}

What is the critical f(x)=\sqrt[3]{x^2(x-2)^2} ?
The critical f(x)=\sqrt[3]{x^2(x-2)^2} is x=0,x=1,x=2