What is the critical (x^2-x)/(x^2-4) ?

The critical (x^2-x)/(x^2-4) is x=2(2-sqrt(3)),x=2(2+sqrt(3))

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critical (x^2-x)/(x^2-4)

critical points

\frac{x ^{2} - x}{x ^{2} - 4}

x = 2 (2 - 3), x = 2 (2 + 3)

Solution steps

\frac{x ^{2} - x}{x ^{2} - 4}

Find where

f^{'} (x)

is equal to zero or undefined

x = 2 (2 - 3), x = 2 (2 + 3), x = - 2, x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - x}{x ^{2} - 4} : x < - 2 or - 2 < x < 2 or x > 2

\frac{x ^{2} - x}{x ^{2} - 4}

is not defined at

x = - 2, x = 2

, therefore:

x = 2 (2 - 3), x = 2 (2 + 3)

f (x) = x^{3} + x^{2} - 5 x + 3

x - 2 + 4 - x

s (t) = 2 t e^{- t}

x + cos (x)

3 ∣ x ∣

What is the critical (x^2-x)/(x^2-4) ?
The critical (x^2-x)/(x^2-4) is x=2(2-sqrt(3)),x=2(2+sqrt(3))