What is the range of f(x)=|x-2|+1 ?

The range of f(x)=|x-2|+1 is f(x)>= 1

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range of f(x)=|x-2|+1

range

f (x) = ∣ x - 2 ∣ + 1

f (x) \geq 1

Interval Notation

[1, \infty)

Solution steps

The range of an absolute function of the form

c ∣ a x + b ∣ + k

f (x) \geq k

k = 1

f (x) \geq 1

(- 2.1) (4.3)

x^{3} + 6 x^{2} + 12 x + 4

3 x - x^{3}

f (x) = 2 - cot (π x - \frac{π}{4})

f (x) = (x - 1)^{3} + 5