What is the critical f(x)=ln(1-ln(x)) ?

The critical f(x)=ln(1-ln(x)) is None

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critical f(x)=ln(1-ln(x))

critical points

f (x) = ln (1 - ln (x))

None

Solution steps

ln (1 - ln (x))

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = e

Identify critical points not in

f (x)

domain

Domain of

ln (1 - ln (x)) : 0 < x < e

ln (1 - ln (x))

is not defined at

x = 0, x = e

, therefore:

None

f (x) = x^{6}

f (x) = 3 x^{2} + 2 x - 1

10 - x^{2} y + 3 x y + x y^{2}

f (x, y) = 2 x + y

\frac{x}{x ^{2} + 13 x + 36}