What is the critical f(x)=6x^2ln(x) ?

The critical f(x)=6x^2ln(x) is x= 1/(sqrt(e))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical f(x)=6x^2ln(x)

critical points

f (x) = 6 x^{2} ln (x)

x = \frac{1}{e}

Solution steps

6 x^{2} ln (x)

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{1}{e}, x = 0

Identify critical points not in

f (x)

domain

Domain of

6 x^{2} ln (x) : x > 0

6 x^{2} ln (x)

is not defined at

x = 0

, therefore:

x = \frac{1}{e}

f (x) = (x^{2} + 12) (4 - x^{2})

y = 3 x^{2} - 2 x + 1

f (x, y) = x^{2} y + y^{3} - 48 y

f (x) = x^{3} + 3 x y^{2} + y^{3} - 15 y - 15 x

f (x) = e^{x} + x^{2}

What is the critical f(x)=6x^2ln(x) ?
The critical f(x)=6x^2ln(x) is x= 1/(sqrt(e))