What is the critical x/(x^2+12x+35) ?

The critical x/(x^2+12x+35) is x=-sqrt(35),x=sqrt(35)

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critical x/(x^2+12x+35)

critical points

\frac{x}{x ^{2} + 12 x + 35}

x = - 35, x = 35

Solution steps

\frac{x}{x ^{2} + 12 x + 35}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 35, x = 35, x = - 7, x = - 5

Identify critical points not in

f (x)

domain

Domain of

\frac{x}{x ^{2} + 12 x + 35} : x < - 7 or - 7 < x < - 5 or x > - 5

\frac{x}{x ^{2} + 12 x + 35}

is not defined at

x = - 7, x = - 5

, therefore:

x = - 35, x = 35

f (x) = x^{5} e^{3 x}

f (x, y) = x^{3} + y^{2} - 6 x y + 6 x + 3 y

f (x, y) = 3 x^{2} - x y + 2 y^{3}

f (x, y) = 2 x^{3} - 6 x^{2} + y^{3} + 15 y^{2}

f (x) = \frac{x ^{4}}{4} - x^{3} - 2 x^{2} + 3

What is the critical x/(x^2+12x+35) ?
The critical x/(x^2+12x+35) is x=-sqrt(35),x=sqrt(35)