What is the critical f(x)= 1/3 x^3-9x+1/3 y^3-4y ?

The critical f(x)= 1/3 x^3-9x+1/3 y^3-4y is (-3,2),(-3,-2),(3,2),(3,-2)

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critical f(x)= 1/3 x^3-9x+1/3 y^3-4y

critical points

f (x) = \frac{1}{3} x^{3} - 9 x + \frac{1}{3} y^{3} - 4 y

(- 3, 2), (- 3, - 2), (3, 2), (3, - 2)

Solution steps

\frac{1}{3} x^{3} - 9 x + \frac{1}{3} y^{3} - 4 y

Find where

\nabla f (x, y)

is equal to zero or undefined

(- 3, 2), (- 3, - 2), (3, 2), (3, - 2)

f (x) = 6 cos (x) + 3 sin^{2} (x)

f (x) = x y + \frac{8}{x} + \frac{8}{y}

f (x, y) = x^{3} - 4 x y + y^{3}

f (x) = x^{4} - 8 x^{3} + 18 x^{2}

f (x) = \frac{( x - 1 ) ^{\frac{1}{5}}}{x + 1}

What is the critical f(x)= 1/3 x^3-9x+1/3 y^3-4y ?
The critical f(x)= 1/3 x^3-9x+1/3 y^3-4y is (-3,2),(-3,-2),(3,2),(3,-2)