What is the range of f(x)=2sqrt(x) ?

The range of f(x)=2sqrt(x) is f(x)>= 0

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range of f(x)=2sqrt(x)

range

f (x) = 2 x

f (x) \geq 0

Interval Notation

[0, \infty)

Solution steps

The range of an radical function of the form

c a x + b + k

f (x) \geq k

k = 0

f (x) \geq 0

f (x) = ∣ 1 - x ∣

cot (\frac{1}{2} x)

2^{x} - 8

f (x) = 36 - x^{2}

f (x) = \frac{1}{( x - 3 )}