What is the critical y=(-2(x^2-1))/(x^2-4) ?

The critical y=(-2(x^2-1))/(x^2-4) is x=0

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critical y=(-2(x^2-1))/(x^2-4)

critical points

y = \frac{- 2 ( x ^{2} - 1 )}{x ^{2} - 4}

x = 0

Solution steps

\frac{- 2 ( x ^{2} - 1 )}{x ^{2} - 4}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = - 2, x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{- 2 ( x ^{2} - 1 )}{x ^{2} - 4} : x < - 2 or - 2 < x < 2 or x > 2

\frac{- 2 ( x ^{2} - 1 )}{x ^{2} - 4}

is not defined at

x = - 2, x = 2

, therefore:

x = 0

f (x) = x^{5 x}

f (x) = 2 x^{3} + x^{2} - 20 x + 5

(12 - 6 x) e^{x}

f (x) = x^{2} - 4 x + 4

3 x^{2} - 6 x - 9

What is the critical y=(-2(x^2-1))/(x^2-4) ?
The critical y=(-2(x^2-1))/(x^2-4) is x=0