What is the critical f(x)=-4xy-x^4-y^4 ?

The critical f(x)=-4xy-x^4-y^4 is (0,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical f(x)=-4xy-x^4-y^4

critical points

f (x) = - 4 x y - x^{4} - y^{4}

(0, 0)

Solution steps

- 4 x y - x^{4} - y^{4}

Find where

\nabla f (x, y)

is equal to zero or undefined

(0, 0)

3 x^{4} - 4 x^{3} - 12 x^{2} + 1

f (x) = x^{2} - 4

f (x) = x^{3} + 9 x^{2}

f (x) = \frac{2 x ^{2}}{x ^{2} - 9}

f (x, y) = x^{2} - 4 x y + 2 y^{2} + 4 x + 8 y + 4

What is the critical f(x)=-4xy-x^4-y^4 ?
The critical f(x)=-4xy-x^4-y^4 is (0,0)