What is the inverse of (x^3-16x)/(4x^2-12x) ?

The inverse of (x^3-16x)/(4x^2-12x) is 2(x+sqrt(x^2-3x+4)),2(x-sqrt(x^2-3x+4))

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inverse of (x^3-16x)/(4x^2-12x)

inverse

\frac{x ^{3} - 16 x}{4 x ^{2} - 12 x}

2 (x + x^{2} - 3 x + 4), 2 (x - x^{2} - 3 x + 4)

Solution steps

y = \frac{x ^{3} - 16 x}{4 x ^{2} - 12 x}

Replace

x

with

y

x = \frac{y ^{3} - 16 y}{4 y ^{2} - 12 y}

Solve for

y, x = \frac{y ^{3} - 16 y}{4 y ^{2} - 12 y}

2 (x + x^{2} - 3 x + 4), 2 (x - x^{2} - 3 x + 4)

f (x) = 3 x + 4 + 3

x^{3} - 6 x^{2} - 15 x - 1

(- 2, 1), (2, 5)

f (x) = \frac{x - 3}{x ^{2} - 9}

f (x) = (10 x^{2} - 9)^{\frac{1}{4}} - x

What is the inverse of (x^3-16x)/(4x^2-12x) ?
The inverse of (x^3-16x)/(4x^2-12x) is 2(x+sqrt(x^2-3x+4)),2(x-sqrt(x^2-3x+4))