en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

critical x+ln(x^2-8)

Solution

critical points

x + ln (x^{2} - 8)

Solution

x = - 4

Solution steps

x + ln (x^{2} - 8)

Find where

f^{'} (x)

is equal to zero or undefined

x = - 4, x = 2, x = - 22, x = 22

Identify critical points not in

f (x)

domain

Domain of

x + ln (x^{2} - 8) : x < - 22 or x > 22

x + ln (x^{2} - 8)

is not defined at

x = 2, x = - 22, x = 22

, therefore:

x = - 4

Graph

Popular Examples

critical y=x^3-3x critical points

y = x^{3} - 3 x

critical x^3-2x^2 critical points

x^{3} - 2 x^{2}

critical f(x)=x^5 critical points

f (x) = x^{5}

critical f(x)=cos(x)+sin^2(x)critical points

f (x) = cos (x) + sin^{2} (x)

critical f(x)=x^2+8/x critical points

f (x) = x^{2} + \frac{8}{x}

Frequently Asked Questions (FAQ)

What is the critical x+ln(x^2-8) ?
The critical x+ln(x^2-8) is x=-4