What is the critical y=(x^2-1)/(2x-1) ?

The critical y=(x^2-1)/(2x-1) is None

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critical y=(x^2-1)/(2x-1)

critical points

y = \frac{x ^{2} - 1}{2 x - 1}

None

Solution steps

\frac{x ^{2} - 1}{2 x - 1}

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{1}{2}

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 1}{2 x - 1} : x < \frac{1}{2} or x > \frac{1}{2}

\frac{x ^{2} - 1}{2 x - 1}

is not defined at

x = \frac{1}{2}

, therefore:

None

f (x) = \frac{( x ^{2} - 1 )}{x ^{2} - 4}

f (x) = \frac{x}{x + 3}

f (x) = \frac{x ^{7} - 4 x ^{6} - 16 x ^{5} + 64 x ^{4}}{x}

f (x, y) = x^{2} + y^{4} + 2 x y

x^{2} - 2 ln (x)