What is the critical f(x)=sin^2(2x) ?

The critical f(x)=sin^2(2x) is x= pi/2 n,x= pi/4+pi/2 n

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critical f(x)=sin^2(2x)

critical points

f (x) = sin^{2} (2 x)

x = \frac{π}{2} n, x = \frac{π}{4} + \frac{π}{2} n

Solution steps

sin^{2} (2 x)

Find where

f^{'} (x)

is equal to zero or undefined

x = \frac{π}{2} n, x = \frac{π}{4} + \frac{π}{2} n

Identify critical points not in

f (x)

domain

Domain of

sin^{2} (2 x) : - \infty < x < \infty

All critical points are in domain

x = \frac{π}{2} n, x = \frac{π}{4} + \frac{π}{2} n

f (x) = x^{\frac{4}{3}} - 4 x^{\frac{1}{3}}

e^{x^{2}}

f (x, y) = e^{- y^{2} - x^{2}} (y^{2} + x^{2})

f (x) = x^{2} + 10 x + 25

f (x) = 2 sin (x) + cos (2 x)

What is the critical f(x)=sin^2(2x) ?
The critical f(x)=sin^2(2x) is x= pi/2 n,x= pi/4+pi/2 n