What is the critical f(x)=3x^4-16x^3+6x^2+72x+1 ?

The critical f(x)=3x^4-16x^3+6x^2+72x+1 is x=-1,x=2,x=3

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critical f(x)=3x^4-16x^3+6x^2+72x+1

critical points

f (x) = 3 x^{4} - 16 x^{3} + 6 x^{2} + 72 x + 1

x = - 1, x = 2, x = 3

Solution steps

3 x^{4} - 16 x^{3} + 6 x^{2} + 72 x + 1

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 2, x = 3

Identify critical points not in

f (x)

domain

Domain of

3 x^{4} - 16 x^{3} + 6 x^{2} + 72 x + 1 : - \infty < x < \infty

All critical points are in domain

x = - 1, x = 2, x = 3

f (x) = - x^{2} + 7 x

f (x) = x e^{- 2 x^{2}}

f (x) = 5 x - 2

x^{3} - 3 x y + y^{3}

f (x, y) = x^{2} + 2 y^{2} + 4 x y + 2 x + 4 y

What is the critical f(x)=3x^4-16x^3+6x^2+72x+1 ?
The critical f(x)=3x^4-16x^3+6x^2+72x+1 is x=-1,x=2,x=3