What is the critical P(x,y)=2x^3+3x^2y-2xy^2-3y^3 ?

The critical P(x,y)=2x^3+3x^2y-2xy^2-3y^3 is (0,0),(0,0)

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critical P(x,y)=2x^3+3x^2y-2xy^2-3y^3

critical points

P (x, y) = 2 x^{3} + 3 x^{2} y - 2 x y^{2} - 3 y^{3}

(0, 0), (0, 0)

Solution steps

2 x^{3} + 3 x^{2} y - 2 x y^{2} - 3 y^{3}

Find where

\nabla f (x, y)

is equal to zero or undefined

(0, 0), (0, 0)

x^{3} - 6 x^{2} + 2

f (x) = e^{- 3.5 x^{2}}

f (x) = 3 x ln (x)

4 y^{3} - 2 x^{3} - y^{2} + 2 x - y

f (x, y) = 3 x^{2} + x y^{2} - 2 x y + 1

What is the critical P(x,y)=2x^3+3x^2y-2xy^2-3y^3 ?
The critical P(x,y)=2x^3+3x^2y-2xy^2-3y^3 is (0,0),(0,0)