What is the critical f(x,y)=ln(x^4+y^6+1) ?

The critical f(x,y)=ln(x^4+y^6+1) is (0,0)

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critical f(x,y)=ln(x^4+y^6+1)

critical points

f (x, y) = ln (x^{4} + y^{6} + 1)

(0, 0)

Solution steps

ln (x^{4} + y^{6} + 1)

Find where

\nabla f (x, y)

is equal to zero or undefined

(0, 0)

f (x, y) = e^{(x^{2} - y^{2})}

f (x, y) = - x^{2} - 4 y^{2} - a x + a x y

f (x) = x^{2} - 81

f (x) = x^{3} - 6 x^{2} + 2

f (x) = x^{3} - 6 x^{2} + 1

What is the critical f(x,y)=ln(x^4+y^6+1) ?
The critical f(x,y)=ln(x^4+y^6+1) is (0,0)