What is the critical f(x)=((x^2+1))/(2x) ?

The critical f(x)=((x^2+1))/(2x) is x=-1,x=1

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critical f(x)=((x^2+1))/(2x)

critical points

f (x) = \frac{( x ^{2} + 1 )}{2 x}

x = - 1, x = 1

Solution steps

\frac{x ^{2} + 1}{2 x}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 1, x = 0

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} + 1}{2 x} : x < 0 or x > 0

\frac{x ^{2} + 1}{2 x}

is not defined at

x = 0

, therefore:

x = - 1, x = 1

y = - \frac{cos ( 2 x )}{2} - 2 sin (x)

y = (2 e^{x}) (I n^{3} x) + 5 x

x^{2} - 25

f (x) = \frac{2 x}{x ^{2} + 4}

f (x) = 5 x^{\frac{2}{3}} - x^{\frac{5}{3}}

What is the critical f(x)=((x^2+1))/(2x) ?
The critical f(x)=((x^2+1))/(2x) is x=-1,x=1